2(3y-1)+5=4(y+2)

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Solution for 2(3y-1)+5=4(y+2) equation: 



2(3y-1)+5=4(y+2)

We move all terms to the left:

2(3y-1)+5-(4(y+2))=0

We multiply parentheses

6y-(4(y+2))-2+5=0



We calculate terms in parentheses: -(4(y+2)), so:

4(y+2)

We multiply parentheses

4y+8

Back to the equation:

-(4y+8)



We add all the numbers together, and all the variables

6y-(4y+8)+3=0

We get rid of parentheses

6y-4y-8+3=0

We add all the numbers together, and all the variables

2y-5=0

We move all terms containing y to the left, all other terms to the right

2y=5

y=5/2

y=2+1/2

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