2(3y-1)-8=6y-10

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Solution for 2(3y-1)-8=6y-10 equation: 



2(3y-1)-8=6y-10

We move all terms to the left:

2(3y-1)-8-(6y-10)=0

We multiply parentheses

6y-(6y-10)-2-8=0

We get rid of parentheses

6y-6y+10-2-8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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