2(3y-1)=-5(1+3y)

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Solution for 2(3y-1)=-5(1+3y) equation: 



2(3y-1)=-5(1+3y)

We move all terms to the left:

2(3y-1)-(-5(1+3y))=0

We add all the numbers together, and all the variables

2(3y-1)-(-5(3y+1))=0

We multiply parentheses

6y-(-5(3y+1))-2=0



We calculate terms in parentheses: -(-5(3y+1)), so:

-5(3y+1)

We multiply parentheses

-15y-5

Back to the equation:

-(-15y-5)



We get rid of parentheses

6y+15y+5-2=0

We add all the numbers together, and all the variables

21y+3=0

We move all terms containing y to the left, all other terms to the right

21y=-3

y=-3/21

y=-1/7

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