2(3y-1)=7y-4

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Solution for 2(3y-1)=7y-4 equation: 



2(3y-1)=7y-4

We move all terms to the left:

2(3y-1)-(7y-4)=0

We multiply parentheses

6y-(7y-4)-2=0

We get rid of parentheses

6y-7y+4-2=0

We add all the numbers together, and all the variables

-1y+2=0

We move all terms containing y to the left, all other terms to the right

-y=-2

y=-2/-1

y=+2

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