2(3y-1.5)+y=18+4y-6

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Solution for 2(3y-1.5)+y=18+4y-6 equation: 



2(3y-1.5)+y=18+4y-6

We move all terms to the left:

2(3y-1.5)+y-(18+4y-6)=0

We add all the numbers together, and all the variables

2(3y-1.5)+y-(4y+12)=0

We add all the numbers together, and all the variables

y+2(3y-1.5)-(4y+12)=0

We multiply parentheses

y+6y-(4y+12)-3=0

We get rid of parentheses

y+6y-4y-12-3=0

We add all the numbers together, and all the variables

3y-15=0

We move all terms containing y to the left, all other terms to the right

3y=15

y=15/3

y=5

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