2(3y-2)+2y=36

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Solution for 2(3y-2)+2y=36 equation: 



2(3y-2)+2y=36

We move all terms to the left:

2(3y-2)+2y-(36)=0

We add all the numbers together, and all the variables

2y+2(3y-2)-36=0

We multiply parentheses

2y+6y-4-36=0

We add all the numbers together, and all the variables

8y-40=0

We move all terms containing y to the left, all other terms to the right

8y=40

y=40/8

y=5

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