2(3y-2)+4=3y+6

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Solution for 2(3y-2)+4=3y+6 equation: 



2(3y-2)+4=3y+6

We move all terms to the left:

2(3y-2)+4-(3y+6)=0

We multiply parentheses

6y-(3y+6)-4+4=0

We get rid of parentheses

6y-3y-6-4+4=0

We add all the numbers together, and all the variables

3y-6=0

We move all terms containing y to the left, all other terms to the right

3y=6

y=6/3

y=2

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