2(3y-2)+4y+1=5y+32

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Solution for 2(3y-2)+4y+1=5y+32 equation: 



2(3y-2)+4y+1=5y+32

We move all terms to the left:

2(3y-2)+4y+1-(5y+32)=0

We add all the numbers together, and all the variables

4y+2(3y-2)-(5y+32)+1=0

We multiply parentheses

4y+6y-(5y+32)-4+1=0

We get rid of parentheses

4y+6y-5y-32-4+1=0

We add all the numbers together, and all the variables

5y-35=0

We move all terms containing y to the left, all other terms to the right

5y=35

y=35/5

y=7

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