2(3y-2)=-3(y+3)

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Solution for 2(3y-2)=-3(y+3) equation: 



2(3y-2)=-3(y+3)

We move all terms to the left:

2(3y-2)-(-3(y+3))=0

We multiply parentheses

6y-(-3(y+3))-4=0



We calculate terms in parentheses: -(-3(y+3)), so:

-3(y+3)

We multiply parentheses

-3y-9

Back to the equation:

-(-3y-9)



We get rid of parentheses

6y+3y+9-4=0

We add all the numbers together, and all the variables

9y+5=0

We move all terms containing y to the left, all other terms to the right

9y=-5

y=-5/9

y=-5/9

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