2(3y-3)+3(y-4)=13

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Solution for 2(3y-3)+3(y-4)=13 equation:


Simplifying
2(3y + -3) + 3(y + -4) = 13

Reorder the terms:
2(-3 + 3y) + 3(y + -4) = 13
(-3 * 2 + 3y * 2) + 3(y + -4) = 13
(-6 + 6y) + 3(y + -4) = 13

Reorder the terms:
-6 + 6y + 3(-4 + y) = 13
-6 + 6y + (-4 * 3 + y * 3) = 13
-6 + 6y + (-12 + 3y) = 13

Reorder the terms:
-6 + -12 + 6y + 3y = 13

Combine like terms: -6 + -12 = -18
-18 + 6y + 3y = 13

Combine like terms: 6y + 3y = 9y
-18 + 9y = 13

Solving
-18 + 9y = 13

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '18' to each side of the equation.
-18 + 18 + 9y = 13 + 18

Combine like terms: -18 + 18 = 0
0 + 9y = 13 + 18
9y = 13 + 18

Combine like terms: 13 + 18 = 31
9y = 31

Divide each side by '9'.
y = 3.444444444

Simplifying
y = 3.444444444

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