2(3y-3)=-3(4y+8)

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Solution for 2(3y-3)=-3(4y+8) equation: 



2(3y-3)=-3(4y+8)

We move all terms to the left:

2(3y-3)-(-3(4y+8))=0

We multiply parentheses

6y-(-3(4y+8))-6=0



We calculate terms in parentheses: -(-3(4y+8)), so:

-3(4y+8)

We multiply parentheses

-12y-24

Back to the equation:

-(-12y-24)



We get rid of parentheses

6y+12y+24-6=0

We add all the numbers together, and all the variables

18y+18=0

We move all terms containing y to the left, all other terms to the right

18y=-18

y=-18/18

y=-1

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