2(3y-4)+3(y+2)=4(2y-1)

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Solution for 2(3y-4)+3(y+2)=4(2y-1) equation: 



2(3y-4)+3(y+2)=4(2y-1)

We move all terms to the left:

2(3y-4)+3(y+2)-(4(2y-1))=0

We multiply parentheses

6y+3y-(4(2y-1))-8+6=0



We calculate terms in parentheses: -(4(2y-1)), so:

4(2y-1)

We multiply parentheses

8y-4

Back to the equation:

-(8y-4)



We add all the numbers together, and all the variables

9y-(8y-4)-2=0

We get rid of parentheses

9y-8y+4-2=0

We add all the numbers together, and all the variables

y+2=0

We move all terms containing y to the left, all other terms to the right

y=-2

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