2(3y-4)+3y=16+y

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Solution for 2(3y-4)+3y=16+y equation:



2(3y-4)+3y=16+y
We move all terms to the left:
2(3y-4)+3y-(16+y)=0
We add all the numbers together, and all the variables
2(3y-4)+3y-(y+16)=0
We add all the numbers together, and all the variables
3y+2(3y-4)-(y+16)=0
We multiply parentheses
3y+6y-(y+16)-8=0
We get rid of parentheses
3y+6y-y-16-8=0
We add all the numbers together, and all the variables
8y-24=0
We move all terms containing y to the left, all other terms to the right
8y=24
y=24/8
y=3

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