2(3y-4)+3y=16+y

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Solution for 2(3y-4)+3y=16+y equation: 



2(3y-4)+3y=16+y

We move all terms to the left:

2(3y-4)+3y-(16+y)=0

We add all the numbers together, and all the variables

2(3y-4)+3y-(y+16)=0

We add all the numbers together, and all the variables

3y+2(3y-4)-(y+16)=0

We multiply parentheses

3y+6y-(y+16)-8=0

We get rid of parentheses

3y+6y-y-16-8=0

We add all the numbers together, and all the variables

8y-24=0

We move all terms containing y to the left, all other terms to the right

8y=24

y=24/8

y=3

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