2(3y-4)+y-1=-16

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Solution for 2(3y-4)+y-1=-16 equation: 



2(3y-4)+y-1=-16

We move all terms to the left:

2(3y-4)+y-1-(-16)=0

We add all the numbers together, and all the variables

y+2(3y-4)+15=0

We multiply parentheses

y+6y-8+15=0

We add all the numbers together, and all the variables

7y+7=0

We move all terms containing y to the left, all other terms to the right

7y=-7

y=-7/7

y=-1

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