2(3y-4)-5=7y+25-(4y+8

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Solution for 2(3y-4)-5=7y+25-(4y+8 equation: 



2(3y-4)-5=7y+25-(4y+8

We move all terms to the left:

2(3y-4)-5-(7y+25-(4y+8)=0

We multiply parentheses

6y-(7y+25-(4y+8)-5-8=0

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