2(3y-4)=0.5(10-y)

Solution for 2(3y-4)=0.5(10-y) equation:

2(3y-4)=0.5(10-y)

We move all terms to the left:

2(3y-4)-(0.5(10-y))=0

We add all the numbers together, and all the variables

2(3y-4)-(0.5(-1y+10))=0

We multiply parentheses

6y-(0.5(-1y+10))-8=0


We calculate terms in parentheses: -(0.5(-1y+10)), so:

0.5(-1y+10)

We multiply parentheses

-0.5y+5

Back to the equation:

-(-0.5y+5)


We get rid of parentheses

6y+0.5y-5-8=0

We add all the numbers together, and all the variables

6.5y-13=0

We move all terms containing y to the left, all other terms to the right

6.5y=13

y=13/6.5

y=2