2(3y-45)=2(2y+30)

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Solution for 2(3y-45)=2(2y+30) equation: 



2(3y-45)=2(2y+30)

We move all terms to the left:

2(3y-45)-(2(2y+30))=0

We multiply parentheses

6y-(2(2y+30))-90=0



We calculate terms in parentheses: -(2(2y+30)), so:

2(2y+30)

We multiply parentheses

4y+60

Back to the equation:

-(4y+60)



We get rid of parentheses

6y-4y-60-90=0

We add all the numbers together, and all the variables

2y-150=0

We move all terms containing y to the left, all other terms to the right

2y=150

y=150/2

y=75

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