2(3y-5)-(y+2)-7=-5(2-3y)-3

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Solution for 2(3y-5)-(y+2)-7=-5(2-3y)-3 equation: 



2(3y-5)-(y+2)-7=-5(2-3y)-3

We move all terms to the left:

2(3y-5)-(y+2)-7-(-5(2-3y)-3)=0

We add all the numbers together, and all the variables

2(3y-5)-(y+2)-(-5(-3y+2)-3)-7=0

We multiply parentheses

6y-(y+2)-(-5(-3y+2)-3)-10-7=0

We get rid of parentheses

6y-y-(-5(-3y+2)-3)-2-10-7=0



We calculate terms in parentheses: -(-5(-3y+2)-3), so:

-5(-3y+2)-3

We multiply parentheses

15y-10-3

We add all the numbers together, and all the variables

15y-13

Back to the equation:

-(15y-13)



We add all the numbers together, and all the variables

5y-(15y-13)-19=0

We get rid of parentheses

5y-15y+13-19=0

We add all the numbers together, and all the variables

-10y-6=0

We move all terms containing y to the left, all other terms to the right

-10y=6

y=6/-10

y=-3/5

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