2(3y-5)=-3(7y-9)

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Solution for 2(3y-5)=-3(7y-9) equation: 



2(3y-5)=-3(7y-9)

We move all terms to the left:

2(3y-5)-(-3(7y-9))=0

We multiply parentheses

6y-(-3(7y-9))-10=0



We calculate terms in parentheses: -(-3(7y-9)), so:

-3(7y-9)

We multiply parentheses

-21y+27

Back to the equation:

-(-21y+27)



We get rid of parentheses

6y+21y-27-10=0

We add all the numbers together, and all the variables

27y-37=0

We move all terms containing y to the left, all other terms to the right

27y=37

y=37/27

y=1+10/27

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