2(3y-5)=2(y-11)-4

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Solution for 2(3y-5)=2(y-11)-4 equation:



2(3y-5)=2(y-11)-4
We move all terms to the left:
2(3y-5)-(2(y-11)-4)=0
We multiply parentheses
6y-(2(y-11)-4)-10=0
We calculate terms in parentheses: -(2(y-11)-4), so:
2(y-11)-4
We multiply parentheses
2y-22-4
We add all the numbers together, and all the variables
2y-26
Back to the equation:
-(2y-26)
We get rid of parentheses
6y-2y+26-10=0
We add all the numbers together, and all the variables
4y+16=0
We move all terms containing y to the left, all other terms to the right
4y=-16
y=-16/4
y=-4

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