2(3y-5)=5-3(y+2)

Solution for 2(3y-5)=5-3(y+2) equation:

2(3y-5)=5-3(y+2)

We move all terms to the left:

2(3y-5)-(5-3(y+2))=0

We multiply parentheses

6y-(5-3(y+2))-10=0


We calculate terms in parentheses: -(5-3(y+2)), so:

5-3(y+2)

determiningTheFunctionDomain
-3(y+2)+5

We multiply parentheses

-3y-6+5

We add all the numbers together, and all the variables

-3y-1

Back to the equation:

-(-3y-1)


We get rid of parentheses

6y+3y+1-10=0

We add all the numbers together, and all the variables

9y-9=0

We move all terms containing y to the left, all other terms to the right

9y=9

y=9/9

y=1