2(3y-6)=10y+10

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Solution for 2(3y-6)=10y+10 equation: 



2(3y-6)=10y+10

We move all terms to the left:

2(3y-6)-(10y+10)=0

We multiply parentheses

6y-(10y+10)-12=0

We get rid of parentheses

6y-10y-10-12=0

We add all the numbers together, and all the variables

-4y-22=0

We move all terms containing y to the left, all other terms to the right

-4y=22

y=22/-4

y=-5+1/2

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