2(3y-7)=38

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Solution for 2(3y-7)=38 equation: 



2(3y-7)=38

We move all terms to the left:

2(3y-7)-(38)=0

We multiply parentheses

6y-14-38=0

We add all the numbers together, and all the variables

6y-52=0

We move all terms containing y to the left, all other terms to the right

6y=52

y=52/6

y=8+2/3

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