2(3y-9)-2=3(y+1)+13

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Solution for 2(3y-9)-2=3(y+1)+13 equation: 



2(3y-9)-2=3(y+1)+13

We move all terms to the left:

2(3y-9)-2-(3(y+1)+13)=0

We multiply parentheses

6y-(3(y+1)+13)-18-2=0



We calculate terms in parentheses: -(3(y+1)+13), so:

3(y+1)+13

We multiply parentheses

3y+3+13

We add all the numbers together, and all the variables

3y+16

Back to the equation:

-(3y+16)



We add all the numbers together, and all the variables

6y-(3y+16)-20=0

We get rid of parentheses

6y-3y-16-20=0

We add all the numbers together, and all the variables

3y-36=0

We move all terms containing y to the left, all other terms to the right

3y=36

y=36/3

y=12

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