2(3z+1)-6(3-2z)=20

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Solution for 2(3z+1)-6(3-2z)=20 equation:


Simplifying
2(3z + 1) + -6(3 + -2z) = 20

Reorder the terms:
2(1 + 3z) + -6(3 + -2z) = 20
(1 * 2 + 3z * 2) + -6(3 + -2z) = 20
(2 + 6z) + -6(3 + -2z) = 20
2 + 6z + (3 * -6 + -2z * -6) = 20
2 + 6z + (-18 + 12z) = 20

Reorder the terms:
2 + -18 + 6z + 12z = 20

Combine like terms: 2 + -18 = -16
-16 + 6z + 12z = 20

Combine like terms: 6z + 12z = 18z
-16 + 18z = 20

Solving
-16 + 18z = 20

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 18z = 20 + 16

Combine like terms: -16 + 16 = 0
0 + 18z = 20 + 16
18z = 20 + 16

Combine like terms: 20 + 16 = 36
18z = 36

Divide each side by '18'.
z = 2

Simplifying
z = 2

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