2(3z+1)=10(z+4)

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Solution for 2(3z+1)=10(z+4) equation: 



2(3z+1)=10(z+4)

We move all terms to the left:

2(3z+1)-(10(z+4))=0

We multiply parentheses

6z-(10(z+4))+2=0



We calculate terms in parentheses: -(10(z+4)), so:

10(z+4)

We multiply parentheses

10z+40

Back to the equation:

-(10z+40)



We get rid of parentheses

6z-10z-40+2=0

We add all the numbers together, and all the variables

-4z-38=0

We move all terms containing z to the left, all other terms to the right

-4z=38

z=38/-4

z=-9+1/2

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