2(3z+1)=2(z+3)

Solution for 2(3z+1)=2(z+3) equation:

Simplifying
2(3z + 1) = 2(z + 3)

Reorder the terms:
2(1 + 3z) = 2(z + 3)
(1 * 2 + 3z * 2) = 2(z + 3)
(2 + 6z) = 2(z + 3)

Reorder the terms:
2 + 6z = 2(3 + z)
2 + 6z = (3 * 2 + z * 2)
2 + 6z = (6 + 2z)

Solving
2 + 6z = 6 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
2 + 6z + -2z = 6 + 2z + -2z

Combine like terms: 6z + -2z = 4z
2 + 4z = 6 + 2z + -2z

Combine like terms: 2z + -2z = 0
2 + 4z = 6 + 0
2 + 4z = 6

Add '-2' to each side of the equation.
2 + -2 + 4z = 6 + -2

Combine like terms: 2 + -2 = 0
0 + 4z = 6 + -2
4z = 6 + -2

Combine like terms: 6 + -2 = 4
4z = 4

Divide each side by '4'.
z = 1

Simplifying
z = 1