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2(3z+1)=6(z+2)-10
We simplify the equation to the form, which is simple to understand
2(3z+1)=6(z+2)-10
Reorder the terms in parentheses
+(+6z+2)=6*(z+2)-10
Remove unnecessary parentheses
+6z+2=+6+*(+z+2+)-10
Reorder the terms in parentheses
+6z+2=+(+6z+12)-10
Remove unnecessary parentheses
+6z+2=+6z+12-10
We move all terms containing z to the left and all other terms to the right.
+6z-6z=+12-10-2
We simplify left and right side of the equation.
z=0
0=0
This equation is an identity, so all real numbers are solutions.
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