2(3z+2)-3(z+1)=

Solution for 2(3z+2)-3(z+1)= equation:

Simplifying
2(3z + 2) + -3(z + 1) = 0

Reorder the terms:
2(2 + 3z) + -3(z + 1) = 0
(2 * 2 + 3z * 2) + -3(z + 1) = 0
(4 + 6z) + -3(z + 1) = 0

Reorder the terms:
4 + 6z + -3(1 + z) = 0
4 + 6z + (1 * -3 + z * -3) = 0
4 + 6z + (-3 + -3z) = 0

Reorder the terms:
4 + -3 + 6z + -3z = 0

Combine like terms: 4 + -3 = 1
1 + 6z + -3z = 0

Combine like terms: 6z + -3z = 3z
1 + 3z = 0

Solving
1 + 3z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 3z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 3z = 0 + -1
3z = 0 + -1

Combine like terms: 0 + -1 = -1
3z = -1

Divide each side by '3'.
z = -0.3333333333

Simplifying
z = -0.3333333333