2(3z+2)=42z-5(z-2)

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Solution for 2(3z+2)=42z-5(z-2) equation:


Simplifying
2(3z + 2) = 42z + -5(z + -2)

Reorder the terms:
2(2 + 3z) = 42z + -5(z + -2)
(2 * 2 + 3z * 2) = 42z + -5(z + -2)
(4 + 6z) = 42z + -5(z + -2)

Reorder the terms:
4 + 6z = 42z + -5(-2 + z)
4 + 6z = 42z + (-2 * -5 + z * -5)
4 + 6z = 42z + (10 + -5z)

Reorder the terms:
4 + 6z = 10 + 42z + -5z

Combine like terms: 42z + -5z = 37z
4 + 6z = 10 + 37z

Solving
4 + 6z = 10 + 37z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-37z' to each side of the equation.
4 + 6z + -37z = 10 + 37z + -37z

Combine like terms: 6z + -37z = -31z
4 + -31z = 10 + 37z + -37z

Combine like terms: 37z + -37z = 0
4 + -31z = 10 + 0
4 + -31z = 10

Add '-4' to each side of the equation.
4 + -4 + -31z = 10 + -4

Combine like terms: 4 + -4 = 0
0 + -31z = 10 + -4
-31z = 10 + -4

Combine like terms: 10 + -4 = 6
-31z = 6

Divide each side by '-31'.
z = -0.1935483871

Simplifying
z = -0.1935483871

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