2(3z+2+4z)=102

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Solution for 2(3z+2+4z)=102 equation: 



2(3z+2+4z)=102

We move all terms to the left:

2(3z+2+4z)-(102)=0

We add all the numbers together, and all the variables

2(7z+2)-102=0

We multiply parentheses

14z+4-102=0

We add all the numbers together, and all the variables

14z-98=0

We move all terms containing z to the left, all other terms to the right

14z=98

z=98/14

z=7

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