2(3z+3)+2(2z)=56

Solution for 2(3z+3)+2(2z)=56 equation:

Simplifying
2(3z + 3) + 2(2z) = 56

Reorder the terms:
2(3 + 3z) + 2(2z) = 56
(3 * 2 + 3z * 2) + 2(2z) = 56
(6 + 6z) + 2(2z) = 56

Remove parenthesis around (2z)
6 + 6z + 2 * 2z = 56

Multiply 2 * 2
6 + 6z + 4z = 56

Combine like terms: 6z + 4z = 10z
6 + 10z = 56

Solving
6 + 10z = 56

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 10z = 56 + -6

Combine like terms: 6 + -6 = 0
0 + 10z = 56 + -6
10z = 56 + -6

Combine like terms: 56 + -6 = 50
10z = 50

Divide each side by '10'.
z = 5

Simplifying
z = 5