2(3z+3)-7=29

Solution for 2(3z+3)-7=29 equation:

Simplifying
2(3z + 3) + -7 = 29

Reorder the terms:
2(3 + 3z) + -7 = 29
(3 * 2 + 3z * 2) + -7 = 29
(6 + 6z) + -7 = 29

Reorder the terms:
6 + -7 + 6z = 29

Combine like terms: 6 + -7 = -1
-1 + 6z = 29

Solving
-1 + 6z = 29

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 6z = 29 + 1

Combine like terms: -1 + 1 = 0
0 + 6z = 29 + 1
6z = 29 + 1

Combine like terms: 29 + 1 = 30
6z = 30

Divide each side by '6'.
z = 5

Simplifying
z = 5