2(3z+3)=4(2z-3)

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Solution for 2(3z+3)=4(2z-3) equation:



2(3z+3)=4(2z-3)
We move all terms to the left:
2(3z+3)-(4(2z-3))=0
We multiply parentheses
6z-(4(2z-3))+6=0
We calculate terms in parentheses: -(4(2z-3)), so:
4(2z-3)
We multiply parentheses
8z-12
Back to the equation:
-(8z-12)
We get rid of parentheses
6z-8z+12+6=0
We add all the numbers together, and all the variables
-2z+18=0
We move all terms containing z to the left, all other terms to the right
-2z=-18
z=-18/-2
z=+9

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