2(3z+3+2z)=106

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Solution for 2(3z+3+2z)=106 equation: 



2(3z+3+2z)=106

We move all terms to the left:

2(3z+3+2z)-(106)=0

We add all the numbers together, and all the variables

2(5z+3)-106=0

We multiply parentheses

10z+6-106=0

We add all the numbers together, and all the variables

10z-100=0

We move all terms containing z to the left, all other terms to the right

10z=100

z=100/10

z=10

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