2(3z+4)=2(3z-2)+13

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Solution for 2(3z+4)=2(3z-2)+13 equation:


Simplifying
2(3z + 4) = 2(3z + -2) + 13

Reorder the terms:
2(4 + 3z) = 2(3z + -2) + 13
(4 * 2 + 3z * 2) = 2(3z + -2) + 13
(8 + 6z) = 2(3z + -2) + 13

Reorder the terms:
8 + 6z = 2(-2 + 3z) + 13
8 + 6z = (-2 * 2 + 3z * 2) + 13
8 + 6z = (-4 + 6z) + 13

Reorder the terms:
8 + 6z = -4 + 13 + 6z

Combine like terms: -4 + 13 = 9
8 + 6z = 9 + 6z

Add '-6z' to each side of the equation.
8 + 6z + -6z = 9 + 6z + -6z

Combine like terms: 6z + -6z = 0
8 + 0 = 9 + 6z + -6z
8 = 9 + 6z + -6z

Combine like terms: 6z + -6z = 0
8 = 9 + 0
8 = 9

Solving
8 = 9

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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