2(3z-)+8=34

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Solution for 2(3z-)+8=34 equation: 



2(3z-)+8=34

We move all terms to the left:

2(3z-)+8-(34)=0

We add all the numbers together, and all the variables

2(+3z)+8-34=0

We add all the numbers together, and all the variables

2(+3z)-26=0

We multiply parentheses

6z-26=0

We move all terms containing z to the left, all other terms to the right

6z=26

z=26/6

z=4+1/3

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