2(3z-1)+12=4(z+8+34)

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Solution for 2(3z-1)+12=4(z+8+34) equation:


Simplifying
2(3z + -1) + 12 = 4(z + 8 + 34)

Reorder the terms:
2(-1 + 3z) + 12 = 4(z + 8 + 34)
(-1 * 2 + 3z * 2) + 12 = 4(z + 8 + 34)
(-2 + 6z) + 12 = 4(z + 8 + 34)

Reorder the terms:
-2 + 12 + 6z = 4(z + 8 + 34)

Combine like terms: -2 + 12 = 10
10 + 6z = 4(z + 8 + 34)

Reorder the terms:
10 + 6z = 4(8 + 34 + z)

Combine like terms: 8 + 34 = 42
10 + 6z = 4(42 + z)
10 + 6z = (42 * 4 + z * 4)
10 + 6z = (168 + 4z)

Solving
10 + 6z = 168 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
10 + 6z + -4z = 168 + 4z + -4z

Combine like terms: 6z + -4z = 2z
10 + 2z = 168 + 4z + -4z

Combine like terms: 4z + -4z = 0
10 + 2z = 168 + 0
10 + 2z = 168

Add '-10' to each side of the equation.
10 + -10 + 2z = 168 + -10

Combine like terms: 10 + -10 = 0
0 + 2z = 168 + -10
2z = 168 + -10

Combine like terms: 168 + -10 = 158
2z = 158

Divide each side by '2'.
z = 79

Simplifying
z = 79

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