2(3z-1)=36

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Solution for 2(3z-1)=36 equation: 



2(3z-1)=36

We move all terms to the left:

2(3z-1)-(36)=0

We multiply parentheses

6z-2-36=0

We add all the numbers together, and all the variables

6z-38=0

We move all terms containing z to the left, all other terms to the right

6z=38

z=38/6

z=6+1/3

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