2(3z-1)=8(z+4)

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Solution for 2(3z-1)=8(z+4) equation: 



2(3z-1)=8(z+4)

We move all terms to the left:

2(3z-1)-(8(z+4))=0

We multiply parentheses

6z-(8(z+4))-2=0



We calculate terms in parentheses: -(8(z+4)), so:

8(z+4)

We multiply parentheses

8z+32

Back to the equation:

-(8z+32)



We get rid of parentheses

6z-8z-32-2=0

We add all the numbers together, and all the variables

-2z-34=0

We move all terms containing z to the left, all other terms to the right

-2z=34

z=34/-2

z=-17

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