2(3z-10)-6=40

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Solution for 2(3z-10)-6=40 equation: 



2(3z-10)-6=40

We move all terms to the left:

2(3z-10)-6-(40)=0

We add all the numbers together, and all the variables

2(3z-10)-46=0

We multiply parentheses

6z-20-46=0

We add all the numbers together, and all the variables

6z-66=0

We move all terms containing z to the left, all other terms to the right

6z=66

z=66/6

z=11

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