2(3z-10)=40

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Solution for 2(3z-10)=40 equation:


Simplifying
2(3z + -10) = 40

Reorder the terms:
2(-10 + 3z) = 40
(-10 * 2 + 3z * 2) = 40
(-20 + 6z) = 40

Solving
-20 + 6z = 40

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 6z = 40 + 20

Combine like terms: -20 + 20 = 0
0 + 6z = 40 + 20
6z = 40 + 20

Combine like terms: 40 + 20 = 60
6z = 60

Divide each side by '6'.
z = 10

Simplifying
z = 10

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