2(3z-2)=20

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Solution for 2(3z-2)=20 equation: 



2(3z-2)=20

We move all terms to the left:

2(3z-2)-(20)=0

We multiply parentheses

6z-4-20=0

We add all the numbers together, and all the variables

6z-24=0

We move all terms containing z to the left, all other terms to the right

6z=24

z=24/6

z=4

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