2(3z-4)+1=3(z+1)

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Solution for 2(3z-4)+1=3(z+1) equation:


Simplifying
2(3z + -4) + 1 = 3(z + 1)

Reorder the terms:
2(-4 + 3z) + 1 = 3(z + 1)
(-4 * 2 + 3z * 2) + 1 = 3(z + 1)
(-8 + 6z) + 1 = 3(z + 1)

Reorder the terms:
-8 + 1 + 6z = 3(z + 1)

Combine like terms: -8 + 1 = -7
-7 + 6z = 3(z + 1)

Reorder the terms:
-7 + 6z = 3(1 + z)
-7 + 6z = (1 * 3 + z * 3)
-7 + 6z = (3 + 3z)

Solving
-7 + 6z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-7 + 6z + -3z = 3 + 3z + -3z

Combine like terms: 6z + -3z = 3z
-7 + 3z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-7 + 3z = 3 + 0
-7 + 3z = 3

Add '7' to each side of the equation.
-7 + 7 + 3z = 3 + 7

Combine like terms: -7 + 7 = 0
0 + 3z = 3 + 7
3z = 3 + 7

Combine like terms: 3 + 7 = 10
3z = 10

Divide each side by '3'.
z = 3.333333333

Simplifying
z = 3.333333333

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