2(3z-4)=5(-8z+18)

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Solution for 2(3z-4)=5(-8z+18) equation: 



2(3z-4)=5(-8z+18)

We move all terms to the left:

2(3z-4)-(5(-8z+18))=0

We multiply parentheses

6z-(5(-8z+18))-8=0



We calculate terms in parentheses: -(5(-8z+18)), so:

5(-8z+18)

We multiply parentheses

-40z+90

Back to the equation:

-(-40z+90)



We get rid of parentheses

6z+40z-90-8=0

We add all the numbers together, and all the variables

46z-98=0

We move all terms containing z to the left, all other terms to the right

46z=98

z=98/46

z=2+3/23

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