2(3z-5)=4(5z+6)

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Solution for 2(3z-5)=4(5z+6) equation: 



2(3z-5)=4(5z+6)

We move all terms to the left:

2(3z-5)-(4(5z+6))=0

We multiply parentheses

6z-(4(5z+6))-10=0



We calculate terms in parentheses: -(4(5z+6)), so:

4(5z+6)

We multiply parentheses

20z+24

Back to the equation:

-(20z+24)



We get rid of parentheses

6z-20z-24-10=0

We add all the numbers together, and all the variables

-14z-34=0

We move all terms containing z to the left, all other terms to the right

-14z=34

z=34/-14

z=-2+3/7

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