2(3z=1)=9z-31

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Solution for 2(3z=1)=9z-31 equation: 



2(3z=1)=9z-31

We move all terms to the left:

2(3z-(1))=0

We multiply parentheses

6z-2=0

We move all terms containing z to the left, all other terms to the right

6z=2

z=2/6

z=1/3

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