2(4+1)+4u=3(2u-1)+8

Solution for 2(4+1)+4u=3(2u-1)+8 equation:

2(4+1)+4u=3(2u-1)+8

We move all terms to the left:

2(4+1)+4u-(3(2u-1)+8)=0

We add all the numbers together, and all the variables

4u-(3(2u-1)+8)+25=0


We calculate terms in parentheses: -(3(2u-1)+8), so:

3(2u-1)+8

We multiply parentheses

6u-3+8

We add all the numbers together, and all the variables

6u+5

Back to the equation:

-(6u+5)


We get rid of parentheses

4u-6u-5+25=0

We add all the numbers together, and all the variables

-2u+20=0

We move all terms containing u to the left, all other terms to the right

-2u=-20

u=-20/-2

u=+10