2(4+2v)=-6(v-8)

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Solution for 2(4+2v)=-6(v-8) equation: 



2(4+2v)=-6(v-8)

We move all terms to the left:

2(4+2v)-(-6(v-8))=0

We add all the numbers together, and all the variables

2(2v+4)-(-6(v-8))=0

We multiply parentheses

4v-(-6(v-8))+8=0



We calculate terms in parentheses: -(-6(v-8)), so:

-6(v-8)

We multiply parentheses

-6v+48

Back to the equation:

-(-6v+48)



We get rid of parentheses

4v+6v-48+8=0

We add all the numbers together, and all the variables

10v-40=0

We move all terms containing v to the left, all other terms to the right

10v=40

v=40/10

v=4

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