2(4+3x)=5(x-4)

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Solution for 2(4+3x)=5(x-4) equation: 



2(4+3x)=5(x-4)

We move all terms to the left:

2(4+3x)-(5(x-4))=0

We add all the numbers together, and all the variables

2(3x+4)-(5(x-4))=0

We multiply parentheses

6x-(5(x-4))+8=0



We calculate terms in parentheses: -(5(x-4)), so:

5(x-4)

We multiply parentheses

5x-20

Back to the equation:

-(5x-20)



We get rid of parentheses

6x-5x+20+8=0

We add all the numbers together, and all the variables

x+28=0

We move all terms containing x to the left, all other terms to the right

x=-28

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